What is the derivative of g(t)= 3/(t^2) ?

The derivative of g(t)= 3/(t^2) is -6/(t^3)

What is the first derivative of g(t)= 3/(t^2) ?

The first derivative of g(t)= 3/(t^2) is -6/(t^3)

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derivative of

g (t) = \frac{3}{t ^{2}}

- \frac{6}{t ^{3}}

Solution steps

\frac{d}{d t} (\frac{3}{t ^{2}})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 \frac{d}{d t} (\frac{1}{t ^{2}})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 3 \frac{d}{d t} (t^{- 2})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 3 (- 2 t^{- 2 - 1})

Simplify

3 (- 2 t^{- 2 - 1}) : - \frac{6}{t ^{3}}

= - \frac{6}{t ^{3}}

x \to 2 lim (5 x + 3)

\frac{d y}{d x} = x

\int cos^{4} (x) - cos^{6} (x) d x

\frac{\partial}{\partial y} (e^{x} + cos (y))

ln (8)

What is the derivative of g(t)= 3/(t^2) ?
The derivative of g(t)= 3/(t^2) is -6/(t^3)
What is the first derivative of g(t)= 3/(t^2) ?
The first derivative of g(t)= 3/(t^2) is -6/(t^3)