What is the solution for y^'+sin(t)y=sin(t),y(0)=7 ?

The solution for y^'+sin(t)y=sin(t),y(0)=7 is y=6e^{cos(t)-1}+1

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y^'+sin(t)y=sin(t),y(0)=7

y^{^{'}} + sin (t) y = sin (t), y (0) = 7

y = 6 e^{c o s (t) - 1} + 1

Solution steps

y^{'} (t) + sin (t) y = sin (t)

Solve separable ODE:

y = 6 e^{c o s (t) - 1} + 1

y = 6 e^{c o s (t) - 1} + 1

y = x^{2} + 9 x, at x = - 8

\frac{d}{d x} (- cos (e^{x}))

\int_{1}^{6} \frac{1}{2 x + 3 + x} d x

\frac{d}{d x} (7 x (x^{3} - 8 x + 2))

x \frac{d y}{d x} - 2 y = 5 x^{3}

What is the solution for y^'+sin(t)y=sin(t),y(0)=7 ?
The solution for y^'+sin(t)y=sin(t),y(0)=7 is y=6e^{cos(t)-1}+1