en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of 1/(y^2)-3/(y^4)

Solution

derivative of

\frac{1}{y ^{2}} - \frac{3}{y ^{4}}

Solution

- \frac{2}{y ^{3}} + \frac{12}{y ^{5}}

Solution steps

\frac{d}{d y} (\frac{1}{y ^{2}} - \frac{3}{y ^{4}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d y} (\frac{1}{y ^{2}}) - \frac{d}{d y} (\frac{3}{y ^{4}})

\frac{d}{d y} (\frac{1}{y ^{2}}) = - \frac{2}{y ^{3}}

\frac{d}{d y} (\frac{3}{y ^{4}}) = - \frac{12}{y ^{5}}

= - \frac{2}{y ^{3}} - (- \frac{12}{y ^{5}})

Simplify

= - \frac{2}{y ^{3}} + \frac{12}{y ^{5}}

Popular Examples

(dy)/(dx)=e^{x-y}

\frac{d y}{d x} = e^{x - y}

tangent of f(x)=x^3ln(2x),\at x=1 tangent of

f (x) = x^{3} ln (2 x), at x = 1

integral from 1 to 9 of sqrt(y)ln(y)

\int_{1}^{9} y ln (y) d y

(\partial)/(\partial x)(x/(sin(2x+3y+z^2)))

\frac{\partial}{\partial x} (\frac{x}{sin ( 2 x + 3 y + z ^{2} )})

derivative of 6sqrt(4x^2+3)derivative of

6 4 x^{2} + 3

Frequently Asked Questions (FAQ)

What is the derivative of 1/(y^2)-3/(y^4) ?
The derivative of 1/(y^2)-3/(y^4) is -2/(y^3)+(12)/(y^5)
What is the first derivative of 1/(y^2)-3/(y^4) ?
The first derivative of 1/(y^2)-3/(y^4) is -2/(y^3)+(12)/(y^5)