What is (\partial)/(\partial u)(3vcos(u)) ?

The answer to (\partial)/(\partial u)(3vcos(u)) is -3vsin(u)

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(\partial)/(\partial u)(3vcos(u))

\frac{\partial}{\partial u} (3 v cos (u))

- 3 v sin (u)

Solution steps

\frac{\partial}{\partial u} (3 v cos (u))

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 3 v \frac{\partial}{\partial u} (cos (u))

Apply the common derivative:

\frac{\partial}{\partial u} (cos (u)) = - sin (u)

= 3 v (- sin (u))

Simplify

= - 3 v sin (u)

\frac{d}{d x} (ln ((x^{2} + 4)^{5}))

x \to 4 lim (\frac{( 2 )}{x - 4})

x \to 2 - lim (\frac{2 x}{x ^{2} - 4})

y^{^{''}} + 8 y^{^{'}} + 25 y = 0, y (0) = 3, y^{^{'}} (0) = - 10

x \to - 2 + lim (\frac{- 7 x}{x + 2})

What is (\partial)/(\partial u)(3vcos(u)) ?
The answer to (\partial)/(\partial u)(3vcos(u)) is -3vsin(u)