What is the solution for (1+x)dy=(y+x)dx ?

The solution for (1+x)dy=(y+x)dx is y=ln(1+x)(1+x)+1+c_{1}(1+x)

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(1+x)dy=(y+x)dx

(1 + x) d y = (y + x) d x

y = ln (1 + x) (1 + x) + 1 + c_{1} (1 + x)

Solution steps

(1 + x) d y = (y + x) d x

Solve linear ODE:

y = ln (1 + x) (1 + x) + 1 + c_{1} (1 + x)

y = ln (1 + x) (1 + x) + 1 + c_{1} (1 + x)

f (x) = x^{2} - x + 2, at x = 1

\int_{- π}^{0} 0 d x

\int_{0}^{4} \frac{1}{( 9 - 3 x ) ^{\frac{1}{3}}} d x

\int 3 x^{2} + C d x

f (x) = 3 x + \frac{5}{x}

What is the solution for (1+x)dy=(y+x)dx ?
The solution for (1+x)dy=(y+x)dx is y=ln(1+x)(1+x)+1+c_{1}(1+x)