What is the sum from n=1(1-1/n) to infinity of n^2 ?

The sum from n=1(1-1/n) to infinity of n^2 is diverges

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sum from n=1(1-1/n) to infinity of n^2

n = 1 (1 - \frac{1}{n}) \sum \infty n^{2}

diverges

Solution steps

n = 1 \cdot (1 - \frac{1}{n}) \sum \infty n^{2}

Apply Series Divergence Test:

diverges

= diverges

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What is the sum from n=1(1-1/n) to infinity of n^2 ?
The sum from n=1(1-1/n) to infinity of n^2 is diverges