What is the integral from 1 to 18 of sqrt(3/x) ?

The integral from 1 to 18 of sqrt(3/x) is 6sqrt(6)-2sqrt(3)

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integral from 1 to 18 of sqrt(3/x)

\int_{1}^{18} \frac{3}{x} d x

66 - 23

Decimal Notation

11.23283 \dots

Solution steps

\int_{1}^{18} \frac{3}{x} d x

Apply Integration By Parts

: [\frac{3}{x} x - \int - \frac{3}{2 x ^{\frac{1}{2}}} d x]_{1}^{18}

= [\frac{3}{x} x - \int - \frac{3}{2 x ^{\frac{1}{2}}} d x]_{1}^{18}

\int - \frac{3}{2 x ^{\frac{1}{2}}} d x = - 3 x

= [\frac{3}{x} x - (- 3 x)]_{1}^{18}

Simplify

= [\frac{3}{x} x + 3 x]_{1}^{18}

Compute the boundaries:

66 - 23

= 66 - 23

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What is the integral from 1 to 18 of sqrt(3/x) ?
The integral from 1 to 18 of sqrt(3/x) is 6sqrt(6)-2sqrt(3)