What is the derivative of x^3-2 ?

The derivative of x^3-2 is 3x^2

What is the first derivative of x^3-2 ?

The first derivative of x^3-2 is 3x^2

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\frac{d}{d x} (x^{3} - 2)

3 x^{2}

Solution steps

\frac{d}{d x} (x^{3} - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (2) = 0

= 3 x^{2} - 0

Simplify

= 3 x^{2}

\int (- 6 x) d x

f (x) = x^{2} + 4, g (x) = - x^{2} - 1, x = - 2, x = 3

f (x) = \frac{x ^{2} - 1}{2 x - 3}

\frac{d ^{2} y}{d t ^{2}} - 4 \frac{d y}{d t} - 5 y = 0

\frac{d}{d x} (\frac{x ^{4} + 3 x ^{2}}{( x ^{2} + 1 ) ^{2}})