What is the derivative of 3x^2+8x+2 ?

The derivative of 3x^2+8x+2 is 6x+8

What is the first derivative of 3x^2+8x+2 ?

The first derivative of 3x^2+8x+2 is 6x+8

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derivative of

3 x^{2} + 8 x + 2

6 x + 8

Solution steps

\frac{d}{d x} (3 x^{2} + 8 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (8 x) + \frac{d}{d x} (2)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (2) = 0

= 6 x + 8 + 0

Simplify

= 6 x + 8

x \to 0 lim (\frac{2 ( x + h ( x ) ) - 2 x}{h ( x )})

y^{^{''}} + y = 0, y (0) = 1, y^{^{'}} (0) = 1

5 t^{3}

f (t) = 6 cos (2 t)

What is the derivative of 3x^2+8x+2 ?
The derivative of 3x^2+8x+2 is 6x+8
What is the first derivative of 3x^2+8x+2 ?
The first derivative of 3x^2+8x+2 is 6x+8