What is the derivative of 3/(x^2-4/(x^3)) ?

The derivative of 3/(x^2-4/(x^3)) is -6/(x^3)+(12)/(x^4)

What is the first derivative of 3/(x^2-4/(x^3)) ?

The first derivative of 3/(x^2-4/(x^3)) is -6/(x^3)+(12)/(x^4)

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\frac{d}{d x} (\frac{3}{x ^{2}} - \frac{4}{x ^{3}})

- \frac{6}{x ^{3}} + \frac{12}{x ^{4}}

Solution steps

\frac{d}{d x} (\frac{3}{x ^{2}} - \frac{4}{x ^{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (\frac{3}{x ^{2}}) - \frac{d}{d x} (\frac{4}{x ^{3}})

\frac{d}{d x} (\frac{3}{x ^{2}}) = - \frac{6}{x ^{3}}

\frac{d}{d x} (\frac{4}{x ^{3}}) = - \frac{12}{x ^{4}}

= - \frac{6}{x ^{3}} - (- \frac{12}{x ^{4}})

Simplify

= - \frac{6}{x ^{3}} + \frac{12}{x ^{4}}

\int_{0}^{1} \frac{ln ( x )}{5 x} d x

y = 2 (x + y) \frac{d y}{d x}

x^{\frac{5}{4}}

\frac{d}{d x} ((sin (x) + cos (x))^{3})

(\frac{1}{2} x)^{3}

What is the derivative of 3/(x^2-4/(x^3)) ?
The derivative of 3/(x^2-4/(x^3)) is -6/(x^3)+(12)/(x^4)
What is the first derivative of 3/(x^2-4/(x^3)) ?
The first derivative of 3/(x^2-4/(x^3)) is -6/(x^3)+(12)/(x^4)