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Popular >

derivative of 1/a sin(b+ax)

Solution

\frac{d}{d x} (\frac{1}{a} sin (b + a x))

Solution

cos (b + a x)

Solution steps

\frac{d}{d x} (\frac{1}{a} sin (b + a x))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{a} \frac{d}{d x} (sin (b + a x))

Apply the chain rule:

cos (b + a x) \frac{d}{d x} (b + a x)

= cos (b + a x) \frac{d}{d x} (b + a x)

\frac{d}{d x} (b + a x) = a

= \frac{1}{a} cos (b + a x) a

Simplify

\frac{1}{a} cos (b + a x) a : cos (b + a x)

= cos (b + a x)

Popular Examples

integral of e^{5x}cos(x)

\int e^{5 x} cos (x) d x

(dy)/(dx)=(((2y+5))/(8x+9))^2

\frac{d y}{d x} = (\frac{( 2 y + 5 )}{8 x + 9})^{2}

derivative of (8sqrt(x)+1/(x^{-5)})

\frac{d}{d x} (\frac{8 x + 1}{x ^{- 5}})

integral of x^{n+2}

\int x^{n + 2} d x

integral of (4x^2+9x+4)/((x^2+1)^2)

\int \frac{4 x ^{2} + 9 x + 4}{( x ^{2} + 1 ) ^{2}} d x

Frequently Asked Questions (FAQ)

What is the derivative of 1/a sin(b+ax) ?
The derivative of 1/a sin(b+ax) is cos(b+ax)
What is the first derivative of 1/a sin(b+ax) ?
The first derivative of 1/a sin(b+ax) is cos(b+ax)