What is the derivative of 5x^3-5x ?

The derivative of 5x^3-5x is 15x^2-5

What is the first derivative of 5x^3-5x ?

The first derivative of 5x^3-5x is 15x^2-5

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\frac{d}{d x} (5 x^{3} - 5 x)

15 x^{2} - 5

Solution steps

\frac{d}{d x} (5 x^{3} - 5 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (5 x^{3}) - \frac{d}{d x} (5 x)

\frac{d}{d x} (5 x^{3}) = 15 x^{2}

\frac{d}{d x} (5 x) = 5

= 15 x^{2} - 5

\frac{\partial}{\partial x} (cos (0.6 x - t))

\int \frac{300}{2 x + 25} d x

\frac{\partial}{\partial x} (sin (\frac{y}{x}))

x \to - 2 lim (2 x^{3} - x^{2} + 7 x - 3)

(2.6) (- 2.6)

What is the derivative of 5x^3-5x ?
The derivative of 5x^3-5x is 15x^2-5
What is the first derivative of 5x^3-5x ?
The first derivative of 5x^3-5x is 15x^2-5