What is the tangent of y=(6x)/(x+2),(4,4) ?

The tangent of y=(6x)/(x+2),(4,4) is y= 1/3 x+8/3

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tangent of y=(6x)/(x+2),(4,4)

tangent of

y = \frac{6 x}{x + 2}, (4, 4)

y = \frac{1}{3} x + \frac{8}{3}

Solution steps

Find the slope of

y = \frac{6 x}{x + 2} : \frac{d y}{d x} = \frac{12}{( x + 2 ) ^{2}}

Compute the slope of

y = \frac{6 x}{x + 2}

(4, 4) : m = \frac{1}{3}

Find the line with slope m=

\frac{1}{3}

and passing through

(4, 4) : y = \frac{1}{3} x + \frac{8}{3}

y = \frac{1}{3} x + \frac{8}{3}

x \to 2 lim (x + 3)

\int \frac{( x - 2 )}{x ^{2} - 7 x + 12} d x

\int \frac{1}{x lo g _{10} ( x )} d x

\int (- 18 x^{2} - 10) csc^{2} (3 x^{3} + 5 x) d x

\frac{d}{d x} (\frac{2 x sin ( x )}{1 + cos ( x )})

What is the tangent of y=(6x)/(x+2),(4,4) ?
The tangent of y=(6x)/(x+2),(4,4) is y= 1/3 x+8/3