What is the sum from n=3 to infinity of (4/11)^{-n} ?

The sum from n=3 to infinity of (4/11)^{-n} is diverges

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sum from n=3 to infinity of (4/11)^{-n}

n = 3 \sum \infty (\frac{4}{11})^{- n}

diverges

Solution steps

n = 3 \sum \infty (\frac{4}{11})^{- n}

Apply Series Ratio Test:

diverges

= diverges

(x)^{(\frac{1}{2})}, - x^{2}, 0, (1)

\int 10 x x d x

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y^{^{'}} + x y = - x^{3}

\frac{d ^{2}}{d x ^{2}} (x^{5} e^{x})

What is the sum from n=3 to infinity of (4/11)^{-n} ?
The sum from n=3 to infinity of (4/11)^{-n} is diverges