What is (\partial)/(\partial x)(x^2+xy-25) ?

The answer to (\partial)/(\partial x)(x^2+xy-25) is 2x+y

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(\partial)/(\partial x)(x^2+xy-25)

\frac{\partial}{\partial x} (x^{2} + x y - 25)

2 x + y

Solution steps

\frac{\partial}{\partial x} (x^{2} + x y - 25)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{2}) + \frac{\partial}{\partial x} (x y) - \frac{\partial}{\partial x} (25)

\frac{\partial}{\partial x} (x^{2}) = 2 x

\frac{\partial}{\partial x} (x y) = y

\frac{\partial}{\partial x} (25) = 0

= 2 x + y - 0

Simplify

= 2 x + y

\int_{a}^{2 a} x d x

\int t^{2} - 4 d t

\frac{d}{d x} (x + x^{3})

\frac{d}{d x} (2 x + \frac{1}{3 x ^{3}})

x + \frac{x ^{3}}{3} - tan (x)

What is (\partial)/(\partial x)(x^2+xy-25) ?
The answer to (\partial)/(\partial x)(x^2+xy-25) is 2x+y