What is the limit as x approaches-1 of x/(x^2+x) ?

The limit as x approaches-1 of x/(x^2+x) is diverges

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limit as x approaches-1 of x/(x^2+x)

x \to - 1 lim (\frac{x}{x ^{2} + x})

diverges

Solution steps

x \to - 1 lim (\frac{x}{x ^{2} + x})

x \to a - lim f (x) \neq = x \to a + lim f (x)

then the limit does not exist

x \to - 1 + lim (\frac{x}{x ^{2} + x}) = \infty

x \to - 1 - lim (\frac{x}{x ^{2} + x}) = - \infty

= diverges

f (x) = e^{x^{2} - 6}

x \to 0 lim (x \cdot (ln (x))^{2})

\frac{\partial}{\partial x} (2 sin (2 x) cos (2 y))

\frac{\partial}{\partial x} (\frac{1}{x + 1})

\int (2 t^{2} - 1)^{2} d t

What is the limit as x approaches-1 of x/(x^2+x) ?
The limit as x approaches-1 of x/(x^2+x) is diverges