What is the derivative of x^2+7x-8 ?

The derivative of x^2+7x-8 is 2x+7

What is the first derivative of x^2+7x-8 ?

The first derivative of x^2+7x-8 is 2x+7

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derivative of

x^{2} + 7 x - 8

2 x + 7

Solution steps

\frac{d}{d x} (x^{2} + 7 x - 8)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (7 x) - \frac{d}{d x} (8)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (7 x) = 7

\frac{d}{d x} (8) = 0

= 2 x + 7 - 0

Simplify

= 2 x + 7

\frac{d}{d x} (π cos (x))

e^{x}, e^{- 3 x}, x = ln (5)

\int \frac{x + 5}{x ^{2} + 9} d x

x \to 2 lim (f (x) + g (x))

\frac{1}{x - 8}

What is the derivative of x^2+7x-8 ?
The derivative of x^2+7x-8 is 2x+7
What is the first derivative of x^2+7x-8 ?
The first derivative of x^2+7x-8 is 2x+7