What is the solution for xy^{'''}-2/x y^'=0 ?

The solution for xy^{'''}-2/x y^'=0 is y=c_{1}x^3+c_{2}+c_{3}ln(x)

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xy^{'''}-2/x y^'=0

x y^{^{'''}} - \frac{2}{x} y^{^{'}} = 0

y = c_{1} x^{3} + c_{2} + c_{3} ln (x)

Solution steps

x y^{'''} (x) - \frac{2}{x} y^{'} (x) = 0

Solve linear ODE:

y = c_{1} x^{3} + c_{2} + c_{3} ln (x)

y = c_{1} x^{3} + c_{2} + c_{3} ln (x)

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What is the solution for xy^{'''}-2/x y^'=0 ?
The solution for xy^{'''}-2/x y^'=0 is y=c_{1}x^3+c_{2}+c_{3}ln(x)