What is the integral from 1 to 3 of xsqrt(x^2+1) ?

The integral from 1 to 3 of xsqrt(x^2+1) is (10sqrt(10)-2sqrt(2))/3

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integral from 1 to 3 of xsqrt(x^2+1)

\int_{1}^{3} x x^{2} + 1 d x

\frac{10 10 - 2 2}{3}

Decimal Notation

9.59811 \dots

Solution steps

\int_{1}^{3} x x^{2} + 1 d x

Apply u-substitution

: \int_{2}^{10} u^{2} d u

= \int_{2}^{10} u^{2} d u

Apply the Power Rule

: [\frac{u ^{3}}{3}]_{2}^{10}

= [\frac{u ^{3}}{3}]_{2}^{10}

Compute the boundaries:

\frac{10 10 - 2 2}{3}

= \frac{10 10 - 2 2}{3}

\frac{d}{d y} (3)

\frac{d}{d x} (x 5 - x)

\frac{cos ( t )}{t}

\int e^{(3 x)} d x

\int \frac{x + 3}{( x - 2 ) ( x + 5 )} d x

What is the integral from 1 to 3 of xsqrt(x^2+1) ?
The integral from 1 to 3 of xsqrt(x^2+1) is (10sqrt(10)-2sqrt(2))/3