What is the derivative of f(x)=(2-5x)/(e^x) ?

The derivative of f(x)=(2-5x)/(e^x) is -(-5x+7)/(e^x)

What is the first derivative of f(x)=(2-5x)/(e^x) ?

The first derivative of f(x)=(2-5x)/(e^x) is -(-5x+7)/(e^x)

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derivative of

f (x) = \frac{2 - 5 x}{e ^{x}}

- \frac{- 5 x + 7}{e ^{x}}

Solution steps

\frac{d}{d x} (\frac{2 - 5 x}{e ^{x}})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{\frac{d}{d x} ( 2 - 5 x ) e ^{x} - \frac{d}{d x} ( e ^{x} ) ( 2 - 5 x )}{( e ^{x} ) ^{2}}

\frac{d}{d x} (2 - 5 x) = - 5

\frac{d}{d x} (e^{x}) = e^{x}

= \frac{( - 5 ) e ^{x} - e ^{x} ( 2 - 5 x )}{( e ^{x} ) ^{2}}

Simplify

\frac{( - 5 ) e ^{x} - e ^{x} ( 2 - 5 x )}{( e ^{x} ) ^{2}} : - \frac{- 5 x + 7}{e ^{x}}

= - \frac{- 5 x + 7}{e ^{x}}

x \to \infty lim (5^{x})

\frac{x}{2 + x}

\frac{\partial}{\partial x} (3 x y^{2} z^{3} - x yz)

x \to - 1 lim (x^{2} - 4 x)

\frac{\partial}{\partial x} (x cos (π y))

What is the derivative of f(x)=(2-5x)/(e^x) ?
The derivative of f(x)=(2-5x)/(e^x) is -(-5x+7)/(e^x)
What is the first derivative of f(x)=(2-5x)/(e^x) ?
The first derivative of f(x)=(2-5x)/(e^x) is -(-5x+7)/(e^x)