What is the solution for y^{''}+ay=0 ?

The solution for y^{''}+ay=0 is y=c_{1}cos(sqrt(a)t)+c_{2}sin(sqrt(a)t)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{''}+ay=0

y^{^{''}} + a y = 0

y = c_{1} cos (a t) + c_{2} sin (a t)

Solution steps

y^{''} (t) + a y (t) = 0

Solve linear ODE:

y = c_{1} cos (a t) + c_{2} sin (a t)

y = c_{1} cos (a t) + c_{2} sin (a t)

n = 1 \sum \infty n^{2}

\int_{- 8}^{8} 64 - x^{2} d x

\frac{d y}{d x} = 3 - 6 x + y - 2 x y

(1 + x) cos (x)

\int \frac{7}{16 + 9 r ^{2}} d r

What is the solution for y^{''}+ay=0 ?
The solution for y^{''}+ay=0 is y=c_{1}cos(sqrt(a)t)+c_{2}sin(sqrt(a)t)