What is (\partial)/(\partial x)(ln(x+7y+6z)) ?

The answer to (\partial)/(\partial x)(ln(x+7y+6z)) is 1/(x+7y+6z)

Popular >

(\partial)/(\partial x)(ln(x+7y+6z))

\frac{\partial}{\partial x} (ln (x + 7 y + 6 z))

\frac{1}{x + 7 y + 6 z}

Solution steps

\frac{\partial}{\partial x} (ln (x + 7 y + 6 z))

Treat

y, z

as constants

Apply the chain rule:

\frac{1}{x + 7 y + 6 z} \frac{\partial}{\partial x} (x + 7 y + 6 z)

= \frac{1}{x + 7 y + 6 z} \frac{\partial}{\partial x} (x + 7 y + 6 z)

\frac{\partial}{\partial x} (x + 7 y + 6 z) = 1

= \frac{1}{x + 7 y + 6 z} \cdot 1

Simplify

= \frac{1}{x + 7 y + 6 z}

x \to 1 lim (\frac{3 sin ( π x ) - sin ( 3 π x )}{x ^{3}})

\frac{s - 5}{s ^{2} - 6 s + 25}

t^{2} - 10 t + 31

\int 1 + 4 a^{2} x^{2} d x

\int ln (x - 2) d x

What is (\partial)/(\partial x)(ln(x+7y+6z)) ?
The answer to (\partial)/(\partial x)(ln(x+7y+6z)) is 1/(x+7y+6z)