What is the tangent of f(x)=(5x)/(x-3),(4,20) ?

The tangent of f(x)=(5x)/(x-3),(4,20) is y=-15x+80

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tangent of f(x)=(5x)/(x-3),(4,20)

tangent of

f (x) = \frac{5 x}{x - 3}, (4, 20)

y = - 15 x + 80

Solution steps

Find the slope of

f (x) = \frac{5 x}{x - 3} : \frac{df ( x )}{d x} = - \frac{15}{( x - 3 ) ^{2}}

Compute the slope of

f (x) = \frac{5 x}{x - 3}

(4, 20) : m = - 15

Find the line with slope m=

- 15

and passing through

(4, 20) : y = - 15 x + 80

y = - 15 x + 80

y = (x + 5)^{\frac{1}{x}}

\int x^{2} (x^{3} + 5)^{9} d x

\frac{d}{d x} (\frac{x ^{2} - 1}{x ^{3} - x})

\int \frac{3 - 6 x}{25 - 9 x ^{2}} d x

\frac{\partial}{\partial x} ((x + y) e^{3 x - 4 y})

What is the tangent of f(x)=(5x)/(x-3),(4,20) ?
The tangent of f(x)=(5x)/(x-3),(4,20) is y=-15x+80