What is (d^2)/(dx^2)((e^x)/(8x+1)) ?

The answer to (d^2)/(dx^2)((e^x)/(8x+1)) is (e^x(64x^2-112x+113))/((8x+1)^3)

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(d^2)/(dx^2)((e^x)/(8x+1))

\frac{d ^{2}}{d x ^{2}} (\frac{e ^{x}}{8 x + 1})

\frac{e ^{x} ( 64 x ^{2} - 112 x + 113 )}{( 8 x + 1 ) ^{3}}

Solution steps

\frac{d ^{2}}{d x ^{2}} (\frac{e ^{x}}{8 x + 1})

\frac{d}{d x} (\frac{e ^{x}}{8 x + 1}) = \frac{8 e ^{x} x - 7 e ^{x}}{( 8 x + 1 ) ^{2}}

= \frac{d}{d x} (\frac{8 e ^{x} x - 7 e ^{x}}{( 8 x + 1 ) ^{2}})

\frac{d}{d x} (\frac{8 e ^{x} x - 7 e ^{x}}{( 8 x + 1 ) ^{2}}) = \frac{e ^{x} ( 64 x ^{2} - 112 x + 113 )}{( 8 x + 1 ) ^{3}}

= \frac{e ^{x} ( 64 x ^{2} - 112 x + 113 )}{( 8 x + 1 ) ^{3}}

ln (ln (x^{2}))

y^{^{'}} - \frac{5}{x} y = \frac{y ^{5}}{x ^{11}}

n = 1 \sum \infty \frac{4}{1 0 ^{n}}

\frac{d}{d x} (\frac{x ^{2}}{x ^{4} + 1})

y = 4 - x^{2}, 2 x + y = 4

What is (d^2)/(dx^2)((e^x)/(8x+1)) ?
The answer to (d^2)/(dx^2)((e^x)/(8x+1)) is (e^x(64x^2-112x+113))/((8x+1)^3)