What is the derivative of z^3-5z+4 ?

The derivative of z^3-5z+4 is 3z^2-5

What is the first derivative of z^3-5z+4 ?

The first derivative of z^3-5z+4 is 3z^2-5

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derivative of

z^{3} - 5 z + 4

3 z^{2} - 5

Solution steps

\frac{d}{d z} (z^{3} - 5 z + 4)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d z} (z^{3}) - \frac{d}{d z} (5 z) + \frac{d}{d z} (4)

\frac{d}{d z} (z^{3}) = 3 z^{2}

\frac{d}{d z} (5 z) = 5

\frac{d}{d z} (4) = 0

= 3 z^{2} - 5 + 0

Simplify

= 3 z^{2} - 5

y = \frac{x + 2}{x - 2}

\int cos (10 x) d x

d y = (9 x + 4 y + 1)^{2} d x

\int tan^{2} (x) sec^{3} (x) d x

\int 4 + \frac{5}{x} d x

What is the derivative of z^3-5z+4 ?
The derivative of z^3-5z+4 is 3z^2-5
What is the first derivative of z^3-5z+4 ?
The first derivative of z^3-5z+4 is 3z^2-5