What is the integral of [x^2cos(x)] ?

The integral of [x^2cos(x)] is x^2sin(x)-2(-xcos(x)+sin(x))+C

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integral of [x^2cos(x)]

\int [x^{2} cos (x)] d x

x^{2} sin (x) - 2 (- x cos (x) + sin (x)) + C

Solution steps

\int x^{2} cos (x) d x

Apply Integration By Parts

: x^{2} sin (x) - \int 2 x sin (x) d x

= x^{2} sin (x) - \int 2 x sin (x) d x

\int 2 x sin (x) d x = 2 (- x cos (x) + sin (x))

= x^{2} sin (x) - 2 (- x cos (x) + sin (x))

Add a constant to the solution

= x^{2} sin (x) - 2 (- x cos (x) + sin (x)) + C

\frac{d}{d x} (9 x^{8} e^{x} + e^{x x^{9}})

\frac{y ^{4}}{4} + \frac{1}{8 y ^{2}}

\int_{1}^{4} - 9 e^{x} d x

(- 3, 7), (2, - 6)

\int 4 x e^{6 x} d x

What is the integral of [x^2cos(x)] ?
The integral of [x^2cos(x)] is x^2sin(x)-2(-xcos(x)+sin(x))+C