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Popular >

f(x)=(1+x)/((2x^2+1)^2)

Solution

f (x) = \frac{1 + x}{( 2 x ^{2} + 1 ) ^{2}}

Solution

Domain : - \infty < x < \infty

Range : \frac{50 - 11 22}{96} \leq f (x) \leq \frac{50 + 11 22}{96}

X Intercepts : (- 1, 0), Y Intercepts : (0, 1)

Asymptotes : Horizontal y = 0

Extreme Points : Minimum (- \frac{4 + 22}{6}, \frac{50 - 11 22}{96}), Maximum (\frac{22 - 4}{6}, \frac{50 + 11 22}{96})

+1

Interval Notation

Domain : (- \infty, \infty)

Range : [\frac{50 - 11 22}{96}, \frac{50 + 11 22}{96}]

Solution steps

Domain of

\frac{1 + x}{( 2 x ^{2} + 1 ) ^{2}} : - \infty < x < \infty

Range of

\frac{1 + x}{( 2 x ^{2} + 1 ) ^{2}} : \frac{50 - 11 22}{96} \leq f (x) \leq \frac{50 + 11 22}{96}

Axis interception points of

\frac{1 + x}{( 2 x ^{2} + 1 ) ^{2}} :

X Intercepts

: (- 1, 0),

Y Intercepts

: (0, 1)

Asymptotes of

\frac{1 + x}{( 2 x ^{2} + 1 ) ^{2}} :

Horizontal

: y = 0

Extreme Points of

\frac{1 + x}{( 2 x ^{2} + 1 ) ^{2}} :

Minimum

(- \frac{4 + 22}{6}, \frac{50 - 11 22}{96}),

Maximum

(\frac{22 - 4}{6}, \frac{50 + 11 22}{96})

Popular Examples

y^'+2y=0,y(1)=1

y^{^{'}} + 2 y = 0, y (1) = 1

yy^'= x/(x^2+1)

y y^{^{'}} = \frac{x}{x ^{2} + 1}

y^{^{'}} + y = e^{x}

laplacetransform e^tt laplace transform

e^{t} t

integral of (1-cos(x))/(csc^2(x))

\int \frac{1 - cos ( x )}{csc ^{2} ( x )} d x

Frequently Asked Questions (FAQ)

What is the f(x)=(1+x)/((2x^2+1)^2) ?
The f(x)=(1+x)/((2x^2+1)^2) is