What is the derivative of-4e^{3x} ?

The derivative of-4e^{3x} is -12e^{3x}

What is the first derivative of-4e^{3x} ?

The first derivative of-4e^{3x} is -12e^{3x}

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\frac{d}{d x} (- 4 e^{3 x})

- 12 e^{3 x}

Solution steps

\frac{d}{d x} (- 4 e^{3 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= - 4 \frac{d}{d x} (e^{3 x})

Apply the chain rule:

e^{3 x} \frac{d}{d x} (3 x)

= e^{3 x} \frac{d}{d x} (3 x)

\frac{d}{d x} (3 x) = 3

= - 4 e^{3 x} \cdot 3

Simplify

= - 12 e^{3 x}

\int \frac{x ^{2}}{256 - 64 x ^{2}} d x

f (x) = x^{3}, at x = - 4

\frac{d}{d x} (arccos (f (x)))

\frac{d}{d x} (- 2 a sin (2 x) + b cos (2 x) \cdot 2)

x \to 0 + lim (\frac{l ( x )}{x ^{3}})

What is the derivative of-4e^{3x} ?
The derivative of-4e^{3x} is -12e^{3x}
What is the first derivative of-4e^{3x} ?
The first derivative of-4e^{3x} is -12e^{3x}