What is the limit as x approaches 8 of 4/((x-8)^2) ?

The limit as x approaches 8 of 4/((x-8)^2) is infinity

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limit as x approaches 8 of 4/((x-8)^2)

x \to 8 lim (\frac{4}{( x - 8 ) ^{2}})

\infty

Solution steps

x \to 8 lim (\frac{4}{( x - 8 ) ^{2}})

x \to a - lim f (x) = x \to a + lim f (x) = L

then

x \to a lim f (x) = L

x \to 8 - lim (\frac{4}{( x - 8 ) ^{2}}) = \infty

x \to 8 + lim (\frac{4}{( x - 8 ) ^{2}}) = \infty

= \infty

\frac{d}{d x} (cos^{3} (x) + sin^{4} (x))

\frac{\partial}{\partial x} (8 ln (cos (x)))

\frac{\partial}{\partial x} (5 sin (3 x) cos (4 y))

y^{^{'}} = - 2 y + 5 t, y (0) = - 4

\int e^{9 x} cos (8 x) d x

What is the limit as x approaches 8 of 4/((x-8)^2) ?
The limit as x approaches 8 of 4/((x-8)^2) is infinity