What is (\partial)/(\partial x)(x^3-3y^2) ?

The answer to (\partial)/(\partial x)(x^3-3y^2) is 3x^2

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(\partial)/(\partial x)(x^3-3y^2)

\frac{\partial}{\partial x} (x^{3} - 3 y^{2})

3 x^{2}

Solution steps

\frac{\partial}{\partial x} (x^{3} - 3 y^{2})

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x^{3}) - \frac{\partial}{\partial x} (3 y^{2})

\frac{\partial}{\partial x} (x^{3}) = 3 x^{2}

\frac{\partial}{\partial x} (3 y^{2}) = 0

= 3 x^{2} - 0

Simplify

= 3 x^{2}

x \to 4 lim (\frac{1}{x})

n = 0 \sum \infty 6 x^{n}

\frac{\partial}{\partial y} (x^{5} - 7 x^{3} y^{3} + y^{6})

\int \frac{2 x + 1}{x ^{2} - 7 x + 12} d x

y = e^{4 x}

What is (\partial)/(\partial x)(x^3-3y^2) ?
The answer to (\partial)/(\partial x)(x^3-3y^2) is 3x^2