What is (\partial)/(\partial x)(sin(6xy+7yz+9xz)) ?

The answer to (\partial)/(\partial x)(sin(6xy+7yz+9xz)) is cos(6xy+7yz+9xz)(6y+9z)

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(\partial)/(\partial x)(sin(6xy+7yz+9xz))

\frac{\partial}{\partial x} (sin (6 x y + 7 yz + 9 x z))

cos (6 x y + 7 yz + 9 x z) (6 y + 9 z)

Solution steps

\frac{\partial}{\partial x} (sin (6 x y + 7 yz + 9 x z))

Treat

y, z

as constants

Apply the chain rule:

cos (6 x y + 7 yz + 9 x z) \frac{\partial}{\partial x} (6 x y + 7 yz + 9 x z)

= cos (6 x y + 7 yz + 9 x z) \frac{\partial}{\partial x} (6 x y + 7 yz + 9 x z)

\frac{\partial}{\partial x} (6 x y + 7 yz + 9 x z) = 6 y + 9 z

= cos (6 x y + 7 yz + 9 x z) (6 y + 9 z)

\int \frac{x + 1}{x - 1} d x

\int (4 x - \frac{2}{x} + 5 sin (x)) d x

x \to \infty lim ((4)^{x})

f^{^{'}} (x) = sec (2 x) tan (2 x) - \frac{4}{x ^{2}}

40 ln (2 x + 1)

What is (\partial)/(\partial x)(sin(6xy+7yz+9xz)) ?
The answer to (\partial)/(\partial x)(sin(6xy+7yz+9xz)) is cos(6xy+7yz+9xz)(6y+9z)