What is the solution for y^{''}+16y=-8sin(4t) ?

The solution for y^{''}+16y=-8sin(4t) is y=c_{1}cos(4t)+c_{2}sin(4t)+tcos(4t)

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y^{''}+16y=-8sin(4t)

y^{^{''}} + 16 y = - 8 sin (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t) + t cos (4 t)

Solution steps

y^{''} (t) + 16 y = - 8 sin (4 t)

Solve linear ODE:

y = c_{1} cos (4 t) + c_{2} sin (4 t) + t cos (4 t)

y = c_{1} cos (4 t) + c_{2} sin (4 t) + t cos (4 t)

\frac{4}{x ^{5}}

\int csc (π) x cot (π) x d x

7 x - 6 x (1.1)

x \to + 0 lim (\frac{e ^{9 x} - 1}{x})

\int_{0}^{5} 2 π x (5 x - x^{2}) d x

What is the solution for y^{''}+16y=-8sin(4t) ?
The solution for y^{''}+16y=-8sin(4t) is y=c_{1}cos(4t)+c_{2}sin(4t)+tcos(4t)