What is the derivative of 2x^3+6x-2 ?

The derivative of 2x^3+6x-2 is 6x^2+6

What is the first derivative of 2x^3+6x-2 ?

The first derivative of 2x^3+6x-2 is 6x^2+6

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\frac{d}{d x} (2 x^{3} + 6 x - 2)

6 x^{2} + 6

Solution steps

\frac{d}{d x} (2 x^{3} + 6 x - 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2 x^{3}) + \frac{d}{d x} (6 x) - \frac{d}{d x} (2)

\frac{d}{d x} (2 x^{3}) = 6 x^{2}

\frac{d}{d x} (6 x) = 6

\frac{d}{d x} (2) = 0

= 6 x^{2} + 6 - 0

Simplify

= 6 x^{2} + 6

\frac{\partial}{\partial u} (uv)

\frac{d y}{d x}, y = x^{x}

x \to 1 lim (\frac{11 x ^{2} - 99}{x ^{2} - 20 x + 51})

1.5 cos (\frac{2 π}{25} x)

2 t

What is the derivative of 2x^3+6x-2 ?
The derivative of 2x^3+6x-2 is 6x^2+6
What is the first derivative of 2x^3+6x-2 ?
The first derivative of 2x^3+6x-2 is 6x^2+6