What is (\partial)/(\partial u)(u+v^2) ?

The answer to (\partial)/(\partial u)(u+v^2) is 1

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(\partial)/(\partial u)(u+v^2)

\frac{\partial}{\partial u} (u + v^{2})

1

Solution steps

\frac{\partial}{\partial u} (u + v^{2})

Treat

v

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial u} (u) + \frac{\partial}{\partial u} (v^{2})

\frac{\partial}{\partial u} (u) = 1

\frac{\partial}{\partial u} (v^{2}) = 0

= 1 + 0

Simplify

= 1

\int_{0}^{5} (x + 1) d x

\int (θ^{2} - csc^{2} (θ)) d θ

y = x^{2}, y = 7 + x

\int e^{4 x} sin (4 x) d x

\frac{1}{( 1 - s ) \cdot ( s ^{2} + 1 )}

What is (\partial)/(\partial u)(u+v^2) ?
The answer to (\partial)/(\partial u)(u+v^2) is 1