What is the solution for (dy)/(dx)-4tan(2x)y=sin(2x) ?

The solution for (dy)/(dx)-4tan(2x)y=sin(2x) is y=-(cos(2x))/6+(c_{1})/(cos^2(2x))

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(dy)/(dx)-4tan(2x)y=sin(2x)

\frac{d y}{d x} - 4 tan (2 x) y = sin (2 x)

y = - \frac{cos ( 2 x )}{6} + \frac{c _{1}}{cos ^{2} ( 2 x )}

Solution steps

\frac{d y}{d x} - 4 tan (2 x) y = sin (2 x)

Solve linear ODE:

y = - \frac{cos ( 2 x )}{6} + \frac{c _{1}}{cos ^{2} ( 2 x )}

y = - \frac{cos ( 2 x )}{6} + \frac{c _{1}}{cos ^{2} ( 2 x )}

x \to 0 - lim (e^{c s c (x)})

n = 1 \sum \infty \frac{e ^{\frac{7}{n}}}{n}

\frac{d}{d x} (p x + b)

x \to 1 + lim (\frac{4}{1 - x})

What is the solution for (dy)/(dx)-4tan(2x)y=sin(2x) ?
The solution for (dy)/(dx)-4tan(2x)y=sin(2x) is y=-(cos(2x))/6+(c_{1})/(cos^2(2x))