What is the derivative of x^3-6x^2-9 ?

The derivative of x^3-6x^2-9 is 3x^2-12x

What is the first derivative of x^3-6x^2-9 ?

The first derivative of x^3-6x^2-9 is 3x^2-12x

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\frac{d}{d x} (x^{3} - 6 x^{2} - 9)

3 x^{2} - 12 x

Solution steps

\frac{d}{d x} (x^{3} - 6 x^{2} - 9)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (6 x^{2}) - \frac{d}{d x} (9)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (6 x^{2}) = 12 x

\frac{d}{d x} (9) = 0

= 3 x^{2} - 12 x - 0

Simplify

= 3 x^{2} - 12 x

x \to 0 + lim (\frac{4}{x} - \frac{4}{∣ x ∣})

t \to 0 lim (t e^{- t})

(790, 77880), (970, 94440)

\int \frac{3}{37} x^{2} d x

What is the derivative of x^3-6x^2-9 ?
The derivative of x^3-6x^2-9 is 3x^2-12x
What is the first derivative of x^3-6x^2-9 ?
The first derivative of x^3-6x^2-9 is 3x^2-12x