What is the derivative of f(x)=8x-3 ?

The derivative of f(x)=8x-3 is 8

What is the first derivative of f(x)=8x-3 ?

The first derivative of f(x)=8x-3 is 8

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derivative of

f (x) = 8 x - 3

8

Solution steps

\frac{d}{d x} (8 x - 3)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (8 x) - \frac{d}{d x} (3)

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (3) = 0

= 8 - 0

Simplify

= 8

f (x) = 2 e^{x} cos (x), at x = 0

\int 0.67 sin (100 π x + \frac{π}{3}) d x

\int ((1 + \frac{1}{x})^{3} (\frac{1}{x ^{2}})) d x

8 + x^{2}

f (t) = - cos (t)

What is the derivative of f(x)=8x-3 ?
The derivative of f(x)=8x-3 is 8
What is the first derivative of f(x)=8x-3 ?
The first derivative of f(x)=8x-3 is 8