What is the derivative of f(x)= 2/(3+x) ?

The derivative of f(x)= 2/(3+x) is -2/((3+x)^2)

What is the first derivative of f(x)= 2/(3+x) ?

The first derivative of f(x)= 2/(3+x) is -2/((3+x)^2)

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derivative of

f (x) = \frac{2}{3 + x}

- \frac{2}{( 3 + x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{2}{3 + x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (\frac{1}{3 + x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= 2 \frac{d}{d x} ((3 + x)^{- 1})

Apply the chain rule:

- \frac{1}{( 3 + x ) ^{2}} \frac{d}{d x} (3 + x)

= - \frac{1}{( 3 + x ) ^{2}} \frac{d}{d x} (3 + x)

\frac{d}{d x} (3 + x) = 1

= 2 (- \frac{1}{( 3 + x ) ^{2}} \cdot 1)

Simplify

2 (- \frac{1}{( 3 + x ) ^{2}} \cdot 1) : - \frac{2}{( 3 + x ) ^{2}}

= - \frac{2}{( 3 + x ) ^{2}}

\frac{d}{d x} (\frac{1}{x ^{2} - 25})

y^{^{''}} + 25 y = sin (5 x)

\int sec^{2} (x) + 9 d x

\int - \frac{5 ^{- x}}{ln ( 5 )} d x

\int - 36 x^{2} - 18 x - 4 d x

What is the derivative of f(x)= 2/(3+x) ?
The derivative of f(x)= 2/(3+x) is -2/((3+x)^2)
What is the first derivative of f(x)= 2/(3+x) ?
The first derivative of f(x)= 2/(3+x) is -2/((3+x)^2)