What is the limit as x approaches 0+of 8/(x^2-x) ?

The limit as x approaches 0+of 8/(x^2-x) is -infinity

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limit as x approaches 0+of 8/(x^2-x)

x \to 0 + lim (\frac{8}{x ^{2} - x})

- \infty

Solution steps

x \to 0 + lim (\frac{8}{x ^{2} - x})

For

x

approaching

0

from the right

, x > 0 \Rightarrow x^{2} - x < 0

The denominator is a negative quantity approaching 0 from the left

= - \infty

(8.4) (4.1)

x \to - 1 - lim (f (x))

\frac{d}{d x} (\frac{a ^{2} + x ^{2}}{x})

\frac{\partial}{\partial x} (x^{2} y - x y^{3})

\frac{d}{d x} (e^{3 x} + 1)

What is the limit as x approaches 0+of 8/(x^2-x) ?
The limit as x approaches 0+of 8/(x^2-x) is -infinity