What is area y=x(x^2-10x+30),y=x^2 ?

The answer to area y=x(x^2-10x+30),y=x^2 is 443/6

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area y=x(x^2-10x+30),y=x^2

area

y = x (x^{2} - 10 x + 30), y = x^{2}

\frac{443}{6}

Decimal Notation

73.83333 \dots

Solution steps

Apply the area formula:

\int_{0}^{6} x (x^{2} - 10 x + 30) - x^{2} d x

Solve

\int_{0}^{6} x (x^{2} - 10 x + 30) - x^{2} d x : \frac{443}{6}

The area is:

= \frac{443}{6}

\int x e^{- 125 x} d x

x^{2} + x + 23, 2 x^{2} + 3

n = 5 \sum \infty \frac{1}{2 7 ^{n}}

x \to 0 lim (sin (sin (x)))

\int \frac{sin ( x )}{1 + cos ^{2} ( x )} d x

What is area y=x(x^2-10x+30),y=x^2 ?
The answer to area y=x(x^2-10x+30),y=x^2 is 443/6