What is the integral from 7 to 9 of (x^2+2x-3) ?

The integral from 7 to 9 of (x^2+2x-3) is 464/3

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integral from 7 to 9 of (x^2+2x-3)

\int_{7}^{9} (x^{2} + 2 x - 3) d x

\frac{464}{3}

Decimal Notation

154.66666 \dots

Solution steps

\int_{7}^{9} x^{2} + 2 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{7}^{9} x^{2} d x + \int_{7}^{9} 2 x d x - \int_{7}^{9} 3 d x

\int_{7}^{9} x^{2} d x = \frac{386}{3}

\int_{7}^{9} 2 x d x = 32

\int_{7}^{9} 3 d x = 6

= \frac{386}{3} + 32 - 6

Simplify

\frac{386}{3} + 32 - 6 : \frac{464}{3}

= \frac{464}{3}

y^{^{''}} + 6 y^{^{'}} + 9 y = 32 e^{t}, y (0) = 1, y^{^{'}} (0) = 7

\frac{d}{d x} ((x^{2} + 1)^{x})

f (x) = ln (1 + e^{x})

∣ x ∣, x^{2} - 6

y^{^{'}} + 2 y = t, y (0) = 1

What is the integral from 7 to 9 of (x^2+2x-3) ?
The integral from 7 to 9 of (x^2+2x-3) is 464/3