What is the derivative of 4x^2+4x ?

The derivative of 4x^2+4x is 8x+4

What is the first derivative of 4x^2+4x ?

The first derivative of 4x^2+4x is 8x+4

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\frac{d}{d x} (4 x^{2} + 4 x)

8 x + 4

Solution steps

\frac{d}{d x} (4 x^{2} + 4 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4 x^{2}) + \frac{d}{d x} (4 x)

\frac{d}{d x} (4 x^{2}) = 8 x

\frac{d}{d x} (4 x) = 4

= 8 x + 4

\int \frac{x + 2}{2 x + 1} d x

(\frac{x - 5}{x + 5})^{4}

10 y^{^{''}} + 1000 y = 50 cos (8 t)

\frac{d}{d x} (e^{- x} (1 - x))

3 π r^{2}

What is the derivative of 4x^2+4x ?
The derivative of 4x^2+4x is 8x+4
What is the first derivative of 4x^2+4x ?
The first derivative of 4x^2+4x is 8x+4