What is the derivative of 4-x^3 ?

The derivative of 4-x^3 is -3x^2

What is the first derivative of 4-x^3 ?

The first derivative of 4-x^3 is -3x^2

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\frac{d}{d x} (4 - x^{3})

- 3 x^{2}

Solution steps

\frac{d}{d x} (4 - x^{3})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (4) - \frac{d}{d x} (x^{3})

\frac{d}{d x} (4) = 0

\frac{d}{d x} (x^{3}) = 3 x^{2}

= 0 - 3 x^{2}

Simplify

= - 3 x^{2}

\frac{d y}{d t} = \frac{t}{t ^{2} y + y}, y (0) = 7

x \to 7 - lim (∣ x - 7 ∣)

n = 1 \sum \infty \frac{7}{n 8 ^{n}}

\int_{- \infty}^{- 1} \frac{3}{x ^{2}} d x

y^{^{''}} + 8 y^{^{'}} + 32 y = - 320 sin (4 x)