What is the derivative of a+bx^2 ?

The derivative of a+bx^2 is 2bx

What is the first derivative of a+bx^2 ?

The first derivative of a+bx^2 is 2bx

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\frac{d}{d x} (a + b x^{2})

2 b x

Solution steps

\frac{d}{d x} (a + b x^{2})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d a}{d x} + \frac{d}{d x} (b x^{2})

\frac{d a}{d x} = 0

\frac{d}{d x} (b x^{2}) = 2 b x

= 0 + 2 b x

Simplify

= 2 b x

x \to - 2 lim (g (x))

y = e^{- 0.6 x}, y = 1.4 x + 1, x = 0, x = 5

\frac{d}{d x} (in (x - 1))

y^{^{''}} - y = e^{- x}

(3 x^{2})^{2 x} (x^{2} + 2 x)^{2}