What is the sum from n=0 to infinity of (1/5)^n ?

The sum from n=0 to infinity of (1/5)^n is 5/4

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sum from n=0 to infinity of (1/5)^n

n = 0 \sum \infty (\frac{1}{5})^{n}

\frac{5}{4}

Solution steps

n = 0 \sum \infty (\frac{1}{5})^{n}

Apply Series Geometric Test:

\frac{5}{4}

= \frac{5}{4}

12 arcsin (e^{\frac{x}{2}})

\frac{7 x}{8}

\frac{d y}{d x} + 5 y = 0, y (0) = 2

f (x) = x^{3} - 4 x + 6, at x = 2

\int \frac{x ^{2} + 1}{( x - 3 ) ( x - 2 ) ^{2}} d x

What is the sum from n=0 to infinity of (1/5)^n ?
The sum from n=0 to infinity of (1/5)^n is 5/4