What is area f(x)=x^2-3,g(x)=5-x^2 ?

The answer to area f(x)=x^2-3,g(x)=5-x^2 is 64/3

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area f(x)=x^2-3,g(x)=5-x^2

area

f (x) = x^{2} - 3, g (x) = 5 - x^{2}

\frac{64}{3}

Decimal Notation

21.33333 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{2} x^{2} - 3 - (5 - x^{2}) d x

Solve

\int_{- 2}^{2} x^{2} - 3 - (5 - x^{2}) d x : \frac{64}{3}

The area is:

= \frac{64}{3}

f (x) = 6 + 4 x

e^{x + 4} + 8

\frac{x - y}{x + y}

\int \frac{y}{1 - y ^{2}} d y

\frac{\partial}{\partial z} (y^{2})

What is area f(x)=x^2-3,g(x)=5-x^2 ?
The answer to area f(x)=x^2-3,g(x)=5-x^2 is 64/3