What is the derivative of-sin(2x-2cos(x)) ?

The derivative of-sin(2x-2cos(x)) is -2cos(2x)+2sin(x)

What is the first derivative of-sin(2x-2cos(x)) ?

The first derivative of-sin(2x-2cos(x)) is -2cos(2x)+2sin(x)

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\frac{d}{d x} (- sin (2 x) - 2 cos (x))

- 2 cos (2 x) + 2 sin (x)

Solution steps

\frac{d}{d x} (- sin (2 x) - 2 cos (x))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= - \frac{d}{d x} (sin (2 x)) - \frac{d}{d x} (2 cos (x))

\frac{d}{d x} (sin (2 x)) = cos (2 x) \cdot 2

\frac{d}{d x} (2 cos (x)) = - 2 sin (x)

= - cos (2 x) \cdot 2 - (- 2 sin (x))

Simplify

= - 2 cos (2 x) + 2 sin (x)

\frac{d}{d x} (\frac{4 x ^{2} + 6 x + 6}{x})

\int x^{3} \cdot ln (2 x) d x

\frac{s + 5}{s ( s ^{2} + 5 s + 6 )}

y^{^{'''}} - y^{^{''}} = x e^{x}

(x^{2} + 4) y = 8, (- 2, 1)

What is the derivative of-sin(2x-2cos(x)) ?
The derivative of-sin(2x-2cos(x)) is -2cos(2x)+2sin(x)
What is the first derivative of-sin(2x-2cos(x)) ?
The first derivative of-sin(2x-2cos(x)) is -2cos(2x)+2sin(x)