What is the derivative of 2cos^2(t) ?

The derivative of 2cos^2(t) is -2sin(2t)

What is the first derivative of 2cos^2(t) ?

The first derivative of 2cos^2(t) is -2sin(2t)

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derivative of

2 cos^{2} (t)

- 2 sin (2 t)

Solution steps

\frac{d}{d t} (2 cos^{2} (t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (cos^{2} (t))

Apply the chain rule:

2 cos (t) \frac{d}{d t} (cos (t))

= 2 cos (t) \frac{d}{d t} (cos (t))

\frac{d}{d t} (cos (t)) = - sin (t)

= 2 \cdot 2 cos (t) (- sin (t))

Simplify

2 \cdot 2 cos (t) (- sin (t)) : - 2 sin (2 t)

= - 2 sin (2 t)

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\int \frac{x}{5 - 4 x ^{2} - x ^{4}} d x

\frac{12 e ^{- s}}{s ( 10 s + 1 )}

What is the derivative of 2cos^2(t) ?
The derivative of 2cos^2(t) is -2sin(2t)
What is the first derivative of 2cos^2(t) ?
The first derivative of 2cos^2(t) is -2sin(2t)