What is the integral from 1 to 9 of sqrt(x)*ln(x) ?

The integral from 1 to 9 of sqrt(x)*ln(x) is 36ln(3)-104/9

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integral from 1 to 9 of sqrt(x)*ln(x)

\int_{1}^{9} x \cdot ln (x) d x

36 ln (3) - \frac{104}{9}

Decimal Notation

27.99448 \dots

Solution steps

\int_{1}^{9} x ln (x) d x

Apply Integration By Parts

: [\frac{2}{3} x^{\frac{3}{2}} ln (x) - \int \frac{2}{3} x^{\frac{1}{2}} d x]_{1}^{9}

= [\frac{2}{3} x^{\frac{3}{2}} ln (x) - \int \frac{2}{3} x^{\frac{1}{2}} d x]_{1}^{9}

\int \frac{2}{3} x^{\frac{1}{2}} d x = \frac{4}{9} x^{\frac{3}{2}}

= [\frac{2}{3} x^{\frac{3}{2}} ln (x) - \frac{4}{9} x^{\frac{3}{2}}]_{1}^{9}

Compute the boundaries:

36 ln (3) - \frac{104}{9}

= 36 ln (3) - \frac{104}{9}

\int x^{2} + x + 2 d x

x = 4 cos (t)

\int_{2}^{4} x \frac{( 2 x - 3 )}{6} d x

n = 2 \sum \infty \frac{1}{n !}

\frac{d}{d x} (\frac{x - 46}{x - 46})

What is the integral from 1 to 9 of sqrt(x)*ln(x) ?
The integral from 1 to 9 of sqrt(x)*ln(x) is 36ln(3)-104/9