What is the integral of 3x^2-4x+7 ?

The integral of 3x^2-4x+7 is x^3-2x^2+7x+C

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integral of 3x^2-4x+7

\int 3 x^{2} - 4 x + 7 d x

x^{3} - 2 x^{2} + 7 x + C

Solution steps

\int 3 x^{2} - 4 x + 7 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 4 x d x + \int 7 d x

\int 3 x^{2} d x = x^{3}

\int 4 x d x = 2 x^{2}

\int 7 d x = 7 x

= x^{3} - 2 x^{2} + 7 x

Add a constant to the solution

= x^{3} - 2 x^{2} + 7 x + C

y = 2 x - x, y = 0

ln (6)

\int x cos^{5} (x^{2}) d x

t \to 0 lim (5 t cot (2 t))

\frac{e ^{- π s}}{s ^{2} + 1}